Home > Not Working > Ajaxrequest Open Not Working

Ajaxrequest Open Not Working

Contents

Let see if you actually get xmlhttp object created by inserting alert(xmlhttp) right before line 12. Comments rayidi: Reasoning 0 Discussion Starter rayidi 3 5 Years Ago I had used so many xmlHttp finctions. For example, POST request are considered more secure than GET request as creating a POST request is relatively harder than creating a GET request. In asynchronous mode, the send method does not wait for a reply but instead returns immediately, so it allows you to perform other operations while a time-consuming task is being performed

I developed my tool to analyze some high-throughput … AJAX Redirect Notworking in XMLHttpRequest 4 replies I'm Working with register module with xmlHttpRequest. This is the same handler we used for the GET method. Am I missing something? if(http.readyState == 4 && http.status == 200) { alert(http.responseText); } } http.send(null); I really hope that this much is clear for you - I am assuming that you know a

Xmlhttprequest Send Not Working

HTML CSS JavaScript Appendix JavaScript - Opened. please help... I tried every thing but don't know what error is.

If you wanted a JavaScript alert you could change your code from Code: document.getElementById("txtHint").innerHTML=xmlhttp.responseText; to this for validation Code: alert(xmlhttp.responseText); Comments on this post kz13  agrees : Solved my problem Join them; it only takes a minute: Sign up GET xmlHTTPrequest not working up vote 1 down vote favorite i am trying to make an ajax commenting system where if a Any ideas? Xmlhttp.open( Get Url True) Not Working Heres my java script code : function loadData(){ var mID=ddItems; var method=2; var xmlhttp; if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); } if (xmlhttp.readyState == 4 || xmlhttp.readyState == 0) {

yes no Example HTML code 4: This example is similar to the previous one, but it uses asynchronous data transfer and displays blinking text while waiting for the server response (the Xmlhttprequest Not Working In Firefox First initialize an XMLHttpRequest object with the open method, then specify the necessary request headers with the setRequestHeader method and finally send the request with the send method. To send the request asynchronously, the async parameter of the open() method has to be set to true: xmlhttp.open("GET", "xmlhttp_info.txt", true); Sending asynchronously requests is a huge improvement for web developers. imp source more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed

demius 2007-02-12 07:59:04 UTC #9 Thanks for your help guys! Window Xmlhttprequest Not Working In Chrome The specified URL must be in the same domain as the current document. Retrieve the content of an XML file Create an XMLHttpRequest to retrieve data from an XML file and display the data in an HTML table. ❮ Previous Next ❯ COLOR PICKER Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts View Site Leaders What's New?

Xmlhttprequest Not Working In Firefox

The params variable was declared in the second line as "lorem=ipsum&name=binny" - so we send two parameters - 'lorem' and 'name' with the values 'ipsum' and 'binny' respectively. that too, I have added, what else were you expecting? –Салман Feb 8 '13 at 5:58 thanks for you help, right now what I am reading, how to ajax Xmlhttprequest Send Not Working But in the POST method, the data to be send will be send as the argument of the send function. Xmlhttprequest Post Not Working I've never come up with a good reason to not use POST though.

php javascript ajax share|improve this question edited Feb 8 '13 at 5:45 asked Feb 8 '13 at 5:39 Mayur 129418 Using a javascript library like jquery would make your Code XMLHTTPRequest Object For the sake of simplicity, we are going to create the XMLHTTPRequest object using the Firefox supported ' XMLHttpRequest()' function. If you wanted a JavaScript alert you could change your code from Code: document.getElementById("txtHint").innerHTML=xmlhttp.responseText; to this for validation Code: alert(xmlhttp.responseText); Thank you very much!!!!! http.onreadystatechange = function() {//Call a function when the state changes. Xmlhttp Open Not Working In Chrome

Are you aware that your page contains errors? Any clue which one ? share|improve this answer edited Feb 8 '13 at 5:59 answered Feb 8 '13 at 5:42 Салман 3,64522039 i have just basic understanding of jquery any example, Is it complete Reply With Quote 05-11-2011,11:22 AM #2 WolfShade View Profile View Forum Posts Registered User Join Date Dec 2002 Location St.

http.send(params); Finally, we send the parameters with the request. Php Ajax One of the following values: false While the operation is in progress the send method does not return. A common JavaScript syntax for using it looks much like this: Example var xhttp = new XMLHttpRequest();xhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) {

current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list.

share|improve this answer answered Jul 19 '13 at 15:28 Rob Lang 1,3151235 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google If you don't, please read a ajax tutorial that explains these parts before continuing. Last Post 18 Hours Ago $(document).ready(function () { var a, b, c d = new RegExp("/^[a-z0-9]*$/"), e = true, f = [ "g": false, "h": false, "i": false, "j": false, "k": Xmlhttprequest Javascript I have tried everything that you said but nothing worked out I am not able to understand...i have seen referred sites demonstrating login form implementation with ajax....why it is not calling

Not sure if Firefox does. Sentence in 'The Little Prince' conjunction Do I need a transit visa to travel through Beijing to Melbourne AU? Cookies improve the way our website works, by using this website you are agreeing to our use of cookies. elem.type.toLowerCase () : ""; // if an input:checked or input:radio is not checked, skip it if (nodeName === "input" && (type === "checkbox" || type === "radio")) { if (!elem.checked) {

If you wish to see the working of this script, I have set up a demo page for Ajax using post. You may have to register before you can post: click the register link above to proceed. Those who searched for and selected the question are expecting JS solutions. –Chad Mx Dec 17 '15 at 20:22 | show 1 more comment up vote 2 down vote function loadData(){ system 2014-10-08 00:39:03 UTC #12 Home Categories FAQ/Guidelines Terms of Service Privacy Policy Powered by Discourse, best viewed with JavaScript enabled Podcast Articles Premium Register Help Remember Me?

Code ajax_form.js register.php